**MATHS-ANSWERS[Rated 1st Answers That Will Be Posted[100%]**

**=======================================**

**Maths-Obj**

**1CBBACCCBBA**

**11ADBBAABCDB**

**21BCADBCCAAB**

**Subscribe now**

**===================================**

**Note**

**Where ever u c**

**^ it means raise to power**

**/ division**

**x multiplication**

**X normal X**

**================================**

**SECTION A ANS ALL QUESTIONS**

**================================**

**1 a)**

**(y -1 ) log 4 ^ 10 = ylog 16 ^ 10**

**log 4 ^ 10 ( y -1 )= log 16 ^ y 10**

**4 ^ ( y -1 )= 16 y**

**4 ^ y -1 = 4 ^ 2 y**

**y- 1 = 2 y**

**-1 = 2 y= y**

**-1 = y**

**y= -y**

**1 b )**

**let the actual time for 5 km / hr be t**

**for 4 km /hr = 30 mint + t**

**4 km /hr =0 . 5 + t**

**distance = 4 (0 . 5 + t )**

**= 2 * 4 t**

**for 5 km /hr , time = t**

**distance =5 t**

**1 + 4 t = 5 t**

**t= 2 hrs**

**actual distance = 5 * 2 = 10 km**

**================================**

**2a)**

**2/3 (3x – 5) – 3/5 (2x – 3) = 3**

**(15) x 2/3 (3x – 5) – 3/5 (15) (2x – 3) = 3(15)**

**10(3x -5) – 9(2x – 3) = 45**

**30x – 50 – 18x + 27 = 45.**

**12x – 23 = 45**

**12x = 45+23**

**12x = 68**

**X = 68/12**

**X = 5.67**

**2b)**

**80 = n+r ( ext. < equal sum of opp int. <s )**

**80 = n+r ———— (i)**

**<UQT = 180 – 88 – n = 92 – n**

**M = 80 + 92 – n**

**M = 172 – n ———– (ii)**

**80 + 92 – n + 180 – m = 180°**

**80 + 92 + 180 – n – m = 180°**

**352 – n – m = 180**

**-n – m = 180 – 352**

**– n – m = – 172°**

**m + n = 172°**

**===============================**

**3a) **

**Tan 23.6° = h/50**

**Cross multiply**

**Tan 23.6° x h/50**

**h = 50 tan 23.6°**

**= 21.844m**

**aprox. 22m**

****

**3b)**

**Area of <TRU = 45cm^2 (Note: This ^ means Raise to power)**

**A = 1/2bh**

**45 = 1/2 x 10 x h**

**45 = 5h**

**h = 9cm**

**Area of < QTUS = 1/2 ( QT + US)h**

**= 1/2 ( 6 + 16)9**

**= 99cm^2**

**================================**

**4 a)**

**T 6 =37**

**T 6 =a + ( 6 – 1 )d**

**T 6 =a + 5 d**

**a + 5 d = 37 – — -( eq1 )**

**s 6 = 147**

**sn = n / 2 (2 a + (n -1 ) d )**

**147 = 3 (2 a + 5 d )**

**49 = 2 a + 5 d**

**2 a+ 5 d = 49 — — (eq 2 )**

**a + 5 d = 37 – –( eq1 )**

**2 a+ 5 d = 49 — -( eq2 )**

**a =12**

**4 b )**

**S 15 = 15 /2 ( 2 (12 )+ 14 d )**

**S 15 = 15 /2 ( 24 + 14 d )**

**from(1 )**

**a + 5 d = 37**

**12 + 5 d = 37**

**5 d =37 -12**

**5 d =25**

**d =5**

**S 15 = 15 /2 ( 24 + 14 (15 )**

**S 15 = 15 / 2 (24 + 70 )**

**S 15 = 15 /2 * 94**

**S 15 = 15 * 42**

**S 15 = 630**

**================================**

**5a)**

**Let bag=B**

**Shoe= S**

**U=120**

**n(BnS)=45, n(s)=x+11, n(b)=x**

**n(SnB’)=x+11-45**

**=x-34**

**n(BnS’) = 45**

**5b)**

**Y – 45 + 45 + Y – 34 = 120**

**2Y – 34 = 120**

**2Y = 120 – 34**

**2Y = 154**

**Y = 154/2**

**Y = 77**

**11+x=77+11**

**= 88**

**Therefor 88 bought shoes costumer**

**5c)**

**n(bag)= 77 customers**

**Pr. =77/120**

**================================**

**SECTION B ANS 5 QUESTIONS ONLY**

**================================**

**10)**

**Sin x = 5/13**

**Using pythagoras rule**

**M^2 = 13^2 – 5^2 (^ means Raise to power)**

**M^2 = 169 – 25**

**M ^2 = 144**

**M = √144**

**M = 12**

**Hence:**

**Cos x – 2sin x / 2tan x**

**12/13 – 2(5/13) / 2(5/12)**

**= 12/13 – 10/23 / 5/6**

**FIND LCM**

**= 12 – 10/13 / 5/6**

**= 12/65**

**10b)**

**Draw a triangle LACB**

**in triangle LCB**

**Hyp^2 = Opp^2 + Adj^2**

**12^2 = 9.6^2 + |CB|^2**

**144 = 92.16 = |CB|^2**

**144 – 92.16 = |CB|^2**

**51.84 = |CB|^2**

**therefore, |CB| = √51.84**

**|CB| = 7.2m**

**|AC| + |CB| =|AB|**

**|AC| + 7.2m = 10m**

**|AC| = 10m – 7.2m**

**|AC| = 2.8m**

**In triangle LCA**

**Hyp^2 = Opp^2 + Adj^2**

**|LA|^2 = |AC|^2 + |LC|^2**

**|LA|^2 = 2.8^2 + 9.6^2**

**|LA|^2 = 7.84 + 92.16**

**|LA|^2 =100**

**|LA| = √100**

**|LA| = 10m**

**10bii)**

**in triangle LCA**

**sinÎ¸ = Opp/Hyp**

**sinÎ¸ = |LC|/|LA|**

**sinÎ¸ = 9.6/10**

**sinÎ¸ = 0.96**

**Î¸ = sin^-1 (0.96)**

**Î¸ = 73.74**

**===============================**

**13ai)**

**given**

**x(*)y=x+y/2**

**i)3(*)2/5=3+2/5/2**

**=(15+2/5)*1/2**

**=17/5*1/2**

**=17/10= 1,7/10**

**13aii)**

**8(*)y=8^1/4**

**=8+y/2 =33/4**

**32+4y=66**

**4y=66-32**

**4y=34**

**y=34/4**

**y=17/2**

**y=8^1/2**

**13b)**

**given DABC**

**AB=(^-4/6) and AC =(3/^-8)**

**so AP =1/2(^-4/6)**

**AP=(^-2/3)**

**hence**

**CP = CA + AP**

**CP= -(3/^8)+(^-2/3)**

**CP = (^-5/11)**

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